A glass slab appears 10cm thick what is the real thickness if refractive index of a glass is 1.5?
apparent htickness = t/ (ref index) = 15
so, real thicknes, t = 1.5 * 10 = 15cm
apparent htickness = t/ (ref index) = 15
so, real thicknes, t = 1.5 * 10 = 15cm
RingKeeper
on November 30th, -0001
10cms.
Connie
on November 30th, -0001
Do ur homework by own
SeeingStripes
on November 30th, -0001
let ‘c’ be the velocity of light in air and ‘v’ be the velocity of light in glass…
as observed glass appears 10 cm. time required by light to travel through slab is 10/c
but had there been no glass it would have travelled in air for distance (say x, which is the actual depth of slab) with a velocity ‘v’
thus time required = x / v
10 /c = x/v
i.e. x = ( v/c) * 10
now since refractive index = vel. of light in air / vel. of light in medium
therefore x= 10/ 1.5
= 6.67 cm (Ans)
pricklycharacter
on November 30th, -0001
Angle of incidence, i.e. the angle of eye-sight with the glass-surface is needed for this question to solve. Thickness will be other than 10 cm, if you move with respect to the glass.
So can not be answered unless anle of incidence is given.