### Physics – Glass?

A rectangular block of glass (n = 1.52) surrounded by liquid carbon disulfide (n = 1.63). A ray of light is incident on the glass at point A with a = 50.0Â° angle of incidence. At what angle of refraction does the ray leave the glass at point B?

Xfactor

on November 30th, -0001

1. At point A – light ray is travelling from CS2 to Glass.

Applying Snell’s Law – sin X / sin Y = ny/nx.

we get Sin 50 / sin Y = 1.52/1.63

Therefore Y = 55.23 degrees.

2. At point B – light ray is travelling from Glass to CS2

Applying Snell’s Law,

we get, sin 55.23 / sin Y = 1.63/1.52

Therefore Y = 49.997 ~= 50 degrees

So the light ray will leave glass again at 50 degrees. It will be parallel to incident beam but at some distance which you can calculate if you know the glass slab thickness.