Before the glass slab is placed in front of one slit:
X = ?L/d, where ? is the wavelength of the light, L is the distance from the slit to the background screen, d is the separation of the slit and X is the distance from the central maxima to the first band of the interference pattern.
After the glass slab is placed in front of a slit, the wavelength ? is changed due to the refraction index of the glass. Hence the path difference of the light is given by:
?X = X(a) – X(g) = L/d [?(a)-?(g)], where X(g) is the distance from the central maxima to the first band of the interference pattern with the glass slab, and X(a) is without the glass slab. ?(g) is the changed wavelength of light due to the glass slab, and ?(a) is the original wavelength without the glass slab.
But we also know that u, the index of fraction of the glass is given by:
u = c/v, where c is the speed of light in vacuum and v is the average velocity of light in the glass slab.
= (L/d) ?(g)(u-1), but (L/d)?(g) is just t, the thickness of the glass
Hence, ?X = (u-1)t
Sarah on November 30th, -0001
This is becuase the speed of light in all the material media is not he same. To insert the correction factor in the path diference which v derive it comes uout (u-1)t as the distance travelled depend on the velocity of light and the velocity of light is the factor on which refractive index depends. Remember the Snells law.
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Johnnyma on January 19th, 2015
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XRumerTest on February 14th, 2015
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feel-planet.com on January 7th, 2016
Assuming D t it would probably be a fairly accurate description of the situation for small ##\theta##. If it was me, I would place the glass on the entry-side of the slit, thus avoiding such inconsistencies.
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Sunburst
on November 30th, -0001
Before the glass slab is placed in front of one slit:
X = ?L/d, where ? is the wavelength of the light, L is the distance from the slit to the background screen, d is the separation of the slit and X is the distance from the central maxima to the first band of the interference pattern.
After the glass slab is placed in front of a slit, the wavelength ? is changed due to the refraction index of the glass. Hence the path difference of the light is given by:
?X = X(a) – X(g) = L/d [?(a)-?(g)], where X(g) is the distance from the central maxima to the first band of the interference pattern with the glass slab, and X(a) is without the glass slab. ?(g) is the changed wavelength of light due to the glass slab, and ?(a) is the original wavelength without the glass slab.
But we also know that u, the index of fraction of the glass is given by:
u = c/v, where c is the speed of light in vacuum and v is the average velocity of light in the glass slab.
u = c/v = f?(a)/f?(g) = ?(a)/?(g) or ?(a)=u?(g)
Therefore, ?X = L/d [?(a)-?(g)] = (L/d) [u?(g)-?(g)]
= (L/d) ?(g)(u-1), but (L/d)?(g) is just t, the thickness of the glass
Hence, ?X = (u-1)t
Sarah
on November 30th, -0001
This is becuase the speed of light in all the material media is not he same. To insert the correction factor in the path diference which v derive it comes uout (u-1)t as the distance travelled depend on the velocity of light and the velocity of light is the factor on which refractive index depends. Remember the Snells law.
IF u want answers to some of more of ur questions related to ur studies just checkout here
http://www.download-studyguides.blogspot…
and check out all the links outta there.THere contains all the stuff may need to get good rank in ur exams.
Best of Luck!!!!
Johnnyma
on January 19th, 2015
Кинопозитив ytrhfvvvvv
XRumerTest
on February 14th, 2015
Hello. And Bye.
feel-planet.com
on January 7th, 2016
Assuming D t it would probably be a fairly accurate description of the situation for small ##\theta##. If it was me, I would place the glass on the entry-side of the slit, thus avoiding such inconsistencies.
Ailina90
on February 2nd, 2016
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on September 10th, 2016
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on October 22nd, 2016
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on December 15th, 2016
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